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1.6x^2-x-35=0
We add all the numbers together, and all the variables
1.6x^2-1x-35=0
a = 1.6; b = -1; c = -35;
Δ = b2-4ac
Δ = -12-4·1.6·(-35)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-15}{2*1.6}=\frac{-14}{3.2} =-4+1/2.66666666667 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+15}{2*1.6}=\frac{16}{3.2} =5 $
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